document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757771>Question 757771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> square root of (3x-2) + square root (11+x) <-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470466 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is impossible because the range of values for the square root fub=ntion os greater than or equal to 0, so the two quantities on the left side of the inequality could never be negative  - and neither could their sum. </SPAN>\n" );
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