document.write( "Question 771700: A square painting is surrounded by a 3-centimeter wide frame. If the total area of the painting plus frame is 961 cm^2, find the dimensions of the painting. Please show the representation, equation and the solution. \n" ); document.write( "
Algebra.Com's Answer #470444 by Cromlix(4381)\"\" \"About 
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If the painting is square and is surrounded
\n" ); document.write( "by a 3cm wide frame.
\n" ); document.write( "The four sides of the painting + frame
\n" ); document.write( "can be represented by 4 *(x + 6)
\n" ); document.write( "The area of a square = length * width
\n" ); document.write( "Area = (x + 6)(x + 6)
\n" ); document.write( "961 = x^2 + 12x + 36
\n" ); document.write( "Rearranging
\n" ); document.write( "x^2 + 12x + 36 - 961 = 0
\n" ); document.write( "x^2 + 12x - 925 = 0
\n" ); document.write( "(x + 37)(x - 25) = 0
\n" ); document.write( "x + 37 = 0
\n" ); document.write( "x = -37 (no answer as x <0)
\n" ); document.write( "x - 25 = 0
\n" ); document.write( "x = 25
\n" ); document.write( "Therefore, the dimensions of the painting
\n" ); document.write( "without its frame is 25cm by 25cm
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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