document.write( "Question 771757: Please help and explain:
\n" ); document.write( "-8 less than or equal to 1-3(x-2) <2
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Algebra.Com's Answer #470430 by oscargut(2103)\"\" \"About 
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Please help and explain:
\n" ); document.write( "-8 less than or equal to 1-3(x-2) <2\r
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\n" ); document.write( "\n" ); document.write( "-8 < = 1-3(x-2) < 2\r
\n" ); document.write( "\n" ); document.write( "substracting 1\r
\n" ); document.write( "\n" ); document.write( "-9 < = -3(x-2) < 1\r
\n" ); document.write( "\n" ); document.write( "if we divide by -3\r
\n" ); document.write( "\n" ); document.write( "3 > = (x-2) > -1/3\r
\n" ); document.write( "\n" ); document.write( "adding 2\r
\n" ); document.write( "\n" ); document.write( "5 >= x > 2-1/3\r
\n" ); document.write( "\n" ); document.write( "5/3 < x < = 5\r
\n" ); document.write( "\n" ); document.write( "Solution: 5/3 < x < = 5\r
\n" ); document.write( "\n" ); document.write( "I can help you with all of your questions at: mthman@gmail.com\r
\n" ); document.write( "\n" ); document.write( "Thanks\r
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