document.write( "Question 66333This question is from textbook An Incremental Development
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document.write( ":  The sum of the digits of a two-digit number is 15. if the digits are reversed, the new number is only 9 more than the original number. What was the original number? \n" );
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| Algebra.Com's Answer #47040 by ptaylor(2198)     You can put this solution on YOUR website! The sum of the digits of a two-digit number is 15. if the digits are reversed, the new number is only 9 more than the original number. What was the original number?\r \n" ); document.write( "\n" ); document.write( "Letx=1st digit \n" ); document.write( "And y= 2nd digit\r \n" ); document.write( "\n" ); document.write( "Now we are told that x+y=15------------our first equation\r \n" ); document.write( "\n" ); document.write( "But the first number is 10x+y\r \n" ); document.write( "\n" ); document.write( "Now we are also told that if the digits are reversed the new number (10y+x) is 9 more that the first number (10x+y). So:\r \n" ); document.write( "\n" ); document.write( "10y+x=10x+y+9 collecting like terms, we have\r \n" ); document.write( "\n" ); document.write( "9y=9x+9 divide by 9 \n" ); document.write( "y=x+1 or \n" ); document.write( "x-y=-1------------our second equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(1) x+y=15 \n" ); document.write( "(2) x-y=-1\r \n" ); document.write( "\n" ); document.write( "Add (1) and (2) \n" ); document.write( "2x=14 \n" ); document.write( "x=7 first digit \r \n" ); document.write( "\n" ); document.write( "substitute x=7 in (1) \n" ); document.write( "7+y=15 \n" ); document.write( "y=15-7 \n" ); document.write( "y=8 second digit\r \n" ); document.write( "\n" ); document.write( "So our first number was 78 and our second number was 87\r \n" ); document.write( "\n" ); document.write( "ck\r \n" ); document.write( "\n" ); document.write( "7+8=15 \n" ); document.write( "15=15 \n" ); document.write( "87 is 9 more than 78\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps -----ptaylor \n" ); document.write( " \n" ); document.write( " |