document.write( "Question 771674: Show that [1/loga (abc)] + [1/logb (abc)] + [1/logc (abc)] = 1\r
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document.write( "My working:
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document.write( " [1/log abc/log a] + [1/log abc/log b] + [1/log abc/log c]
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document.write( "=[log a/log abc] + [log b/log abc] + [log c/log abc]
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document.write( "=[log (a*b*c)] / [log (abc)^3]
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document.write( "=log (abc) / log (abc)^3
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document.write( "=1/3
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document.write( "My answer is is 1/3, it's wrong. I should prove that the answer is equals to 1. Please help me. \n" );
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Algebra.Com's Answer #470357 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Your working start is good: \n" ); document.write( " \n" ); document.write( "= \n" ); document.write( "Then, you forget that you are adding fractions with a common denominator, and multiply the denominators instead of leaving the common denominator alone, and just adding the numerators,like this: \n" ); document.write( "= \n" ); document.write( "That kind of confusion happens to most of us now and then. \n" ); document.write( "Unfortunately, once we make a mistake like that we cannot detect it by ourselves. \n" ); document.write( "We need help from a pair of fresh, unbiased eyes. \n" ); document.write( " |