document.write( "Question 771638: Find the equation of the circle in the form X^2+y^2+Dx+Ey+F=0 of the circle through points (1,1) (2,-1), (2,3)
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Algebra.Com's Answer #470347 by MathLover1(20850)\"\" \"About 
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Consider the general equation of a circle as \"X%5E2+%2B+Y%5E2+%2B+DX+%2B+EY+%2B+F+=+0\".\r
\n" ); document.write( "\n" ); document.write( "given: points (\"1\",\"1\") (\"2\",\"-1\"), (\"2\",\"3\")\r
\n" ); document.write( "\n" ); document.write( "Using the given three points we derive our equation :\r
\n" ); document.write( "\n" ); document.write( "From the point (\"1\",\"1\") we get the equation \r
\n" ); document.write( "\n" ); document.write( "\"1%2B+1+%2B+D+%2B+E+%2B+F+=+0\" or\r
\n" ); document.write( "\n" ); document.write( "\"D+%2B+E+%2B+F%2B+2+=+0\" ........ equation 1\r
\n" ); document.write( "\n" ); document.write( "From the point (\"2\",\"-1\") we get \r
\n" ); document.write( "\n" ); document.write( "\"4+%2B+1+%2B+2D+-E+%2B+F+=+0\" or\r
\n" ); document.write( "\n" ); document.write( "\"2D+-E+%2B+F%2B5+=+0\"........ equation 2\r
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\n" ); document.write( "\n" ); document.write( "From the point (\"2\",\"3\") we get \r
\n" ); document.write( "\n" ); document.write( "\"4+%2B+9+%2B2D+%2B+3E+%2B+F+=+0\" or \r
\n" ); document.write( "\n" ); document.write( "\"2D+%2B+3E+%2B+F%2B13+=+0\"....... equation 3\r
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\n" ); document.write( "\n" ); document.write( "We now have a system of three equations :\r
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\n" ); document.write( "\n" ); document.write( "\"D+%2B+E+%2B+F%2B+2+=+0\" ........ equation 1\r
\n" ); document.write( "\n" ); document.write( "\"2D+-E+%2B+F%2B5+=+0\"........ equation 2\r
\n" ); document.write( "\n" ); document.write( "\"2D+%2B+3E+%2B+F%2B13+=+0\"....... equation 3\r
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\n" ); document.write( "\n" ); document.write( "We now use elimination method to find the value of \"D\",\"+E\" and \"F\".\r
\n" ); document.write( "\n" ); document.write( "Using equation 1 and eq. 2 to eliminate \"F\", we do this by subtracting equation 2 from eq. 1 :\r
\n" ); document.write( "\n" ); document.write( "\"D+%2B+E+%2B+F%2B+2-%28+2D+-E+%2B+F%2B5+%29=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"D+%2B+E+%2B+F%2B+2-2D+%2BE+-+F-5+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"2E+-2D-3+=+0\"..... let this be equation 4\r
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\n" ); document.write( "\n" ); document.write( "Using Equation 2 and eqn 3, if we subtract eq. 3 from eq. 2 we can eliminate \"F\" and \"D\":\r
\n" ); document.write( "\n" ); document.write( "\"2D+-E+%2B+F%2B5+-%282D+%2B+3E+%2B+F%2B13+%29=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"2D+-E+%2B+F%2B5+-2D-3E+-+F-13+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"-E+%2B5+-3E+-13+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"-4E++-8+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"-E++-2+=+0\" => \"highlight%28E+=-2%29\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.4 and plug in \"E\"\r
\n" ); document.write( "\n" ); document.write( "\"2%28-2%29+-2D-3+=+0\".......solve for \"D\"\r
\n" ); document.write( "\n" ); document.write( "\"-4+-3+=+2D\"\r
\n" ); document.write( "\n" ); document.write( "\"-7+=+2D\"\r
\n" ); document.write( "\n" ); document.write( "\"-7+%2F2=+D\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28D=-3.5%29\"\r
\n" ); document.write( "\n" ); document.write( "go back to eq.1 and plug in \"E\" and \"D\" and solve for \"F\"\r
\n" ); document.write( "\n" ); document.write( "\"-3.5-2+%2B+F%2B+2+=+0\" ........ equation 1\r
\n" ); document.write( "\n" ); document.write( "\"-3.5+%2B+F+=+0\"\r
\n" ); document.write( "\n" ); document.write( " \"highlight%28F+=+3.5%29\"\r
\n" ); document.write( "\n" ); document.write( "We get this general equation by substituting \r
\n" ); document.write( "\n" ); document.write( "\"D+=+-3.5\", \"E+=+-2\" and \"F+=+3.5\" to the general equation of the circle \r
\n" ); document.write( "\n" ); document.write( "\"X%5E2+%2B+Y%5E2+%2B+DX+%2B+EY+%2B+F+=+0\":\r
\n" ); document.write( "\n" ); document.write( "\"X%5E2+%2B+Y%5E2-3.5X+-2Y+%2B+3.5+=+0\"\r
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