document.write( "Question 771600: Two cyclist ride in opposite directions and after 3 hours they are 87 kilometres from each other.if however they ride in the same direction the one is 9 km ahead of the other,after 3 hours.determine each one's velocity.\r
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Algebra.Com's Answer #470338 by mananth(16946) You can put this solution on YOUR website! Two cyclist ride in opposite directions and after 3 hours they are 87 kilometres from each other.if however they ride in the same direction the one is 9 km ahead of the other,after 3 hours.determine each one's velocity.\r \n" ); document.write( "\n" ); document.write( "let speed of one be x and the other y kph\r \n" ); document.write( "\n" ); document.write( "Case I \n" ); document.write( "they are moving away. add their speeds \n" ); document.write( "d=rt\r \n" ); document.write( "\n" ); document.write( "(x+y)*3=87 \n" ); document.write( "/3 \n" ); document.write( "x+y=29....................(1)\r \n" ); document.write( "\n" ); document.write( "distance traveled by first is 3x \n" ); document.write( "distance traveled by second = 3Y \n" ); document.write( "3X-3Y=9 \n" ); document.write( "/3 \n" ); document.write( "X-Y=3.............................(2)\r \n" ); document.write( "\n" ); document.write( "add (1) & (2) \n" ); document.write( "2x=32 \n" ); document.write( "/2 \n" ); document.write( "x=16 speed of first is 16 kph \n" ); document.write( "x-y=3 \n" ); document.write( "plug x=16\r \n" ); document.write( "\n" ); document.write( "speed of second = 13 kph\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |