document.write( "Question 771602: $9000 is invested in two accounts. Account A pays 4% annual interest and account B pay 6% annual interest. In one year a total of $383 is earned in interest. How much was invested in each account. \n" ); document.write( "
Algebra.Com's Answer #470337 by mananth(16946)\"\" \"About 
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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 6.00% per annum ------------ Amount invested = y =
\n" ); document.write( " 9000
\n" ); document.write( "Interest----- 383
\n" ); document.write( "
\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 6.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 9000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 6.00% y= 383
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 6 y= 38300.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -36000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 2 y= 2300
\n" ); document.write( "divide by 2
\n" ); document.write( " y = 1150
\n" ); document.write( "Part I 4.00% $ 7850
\n" ); document.write( "Part II 6.00% $ 1150
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "7850 --------- 4.00% ------- 314.00
\n" ); document.write( "1150 ------------- 6.00% ------- 69.00
\n" ); document.write( "Total -------------------- 383.00
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\n" ); document.write( "m.ananth@hotmail.ca
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