document.write( "Question 771505: which number comes next
\n" ); document.write( "2,5,14,41,122
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Algebra.Com's Answer #470265 by pragya.ban@gmail.com(32)\"\" \"About 
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which number comes next
\n" ); document.write( "2,5,14,41,122\r
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\n" ); document.write( "\n" ); document.write( "As you look into the sequence, you can see the pattern is: 3x-1=y
\n" ); document.write( " (where x is the previous number in the sequence and y is the next number)\r
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\n" ); document.write( "\n" ); document.write( "3(2)-1= 5\r
\n" ); document.write( "\n" ); document.write( "3(5)-1= 14\r
\n" ); document.write( "\n" ); document.write( "3(14)-1= 41\r
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\n" ); document.write( "\n" ); document.write( "and so on... so to find out which number comes next, input 122 for x and find out y:\r
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\n" ); document.write( "\n" ); document.write( "3(122)-1\r
\n" ); document.write( "\n" ); document.write( "366-1\r
\n" ); document.write( "\n" ); document.write( "365\r
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\n" ); document.write( "\n" ); document.write( "So the next number in the sequence is 365
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