document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=771423>Question 771423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many yards of material from a 24-yard length of cloth remain after 3 pieces, each 31/2 yards long, and 5 pieces, each 21/4 yards long, are removed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470253 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 * 3 1/2 = 10 1/2 yards<BR>\n" );
document.write( "5 * 2 1/4 = 11 1/4 yards<BR>\n" );
document.write( "Added<BR>\n" );
document.write( "21 3/4 yards<BR>\n" );
document.write( "24 yards - 21 3/4 yards = 2 1/4 yards left.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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