document.write( "Question 771326: hey, this makes two solutions.one is 24 percent acid the rest is water and the other is 41 percent acid is about how much of each solution does she need to do 50 gallons of a solution that is 31 percent 250 gallons of the solution that is 31 percent acid\r
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Algebra.Com's Answer #470175 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Your question is confusing. Are you asking two questions? \r
\n" ); document.write( "\n" ); document.write( "Given information: 24% acid solution and 41% acid solution.
\n" ); document.write( "Wanted maybe: 50 gallons of 31% solution; and 250 gallons of 31% acid solution.\r
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\n" ); document.write( "\n" ); document.write( "Let V = volume in gallons of the resulting solution when the two different concentrations are mixed.
\n" ); document.write( "Let x = volume of the 24% acid
\n" ); document.write( "let y = volume of the 41% acid\r
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\n" ); document.write( "\n" ); document.write( "The initial untreated system: \"%2824x%2B41y%29%2FV=31\" and \"x%2By=V\"\r
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\n" ); document.write( "\n" ); document.write( "Dealing with the rational equation,
\n" ); document.write( "\"24x%2B41y=31V\"
\n" ); document.write( "So the system you can use to solve for x and y could be
\n" ); document.write( "\"highlight%2824x%2B41y=31V%29\" and \"highlight%28x%2By=V%29\"\r
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\n" ); document.write( "\n" ); document.write( "Pushing a little further, use the volume sum as 24x+24y=24V since this will allow elimination of the x terms:
\n" ); document.write( "\"24x%2B41y-%2824x%2B24y%29=31V-24V\"
\n" ); document.write( "\"41y-24y=7V\"
\n" ); document.write( "\"17y=7V\"
\n" ); document.write( "\"highlight%28y=7V%2F17%29\"
\n" ); document.write( "Substitute this into the volume sum to find x:
\n" ); document.write( "\"x=V-y\"
\n" ); document.write( "\"x=V-%287V%2F17%29\"
\n" ); document.write( "\"x=%2817-7V%29%2F17\"
\n" ); document.write( "\"highlight%28x=10V%2F17%29\"
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