document.write( "Question 771371: My teacher would like us to answer her question & her question is what is wrong with this quadratic equation which is 52-x2+x=10 and the 2 on beside the x should be an exponent!!\r
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Algebra.Com's Answer #470163 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "What is wrong with:\r\n" );
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document.write( "   52 - x² + x = 10  ?\r\n" );
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document.write( "First of all it doesn't have 0 on the right side.\r\n" );
document.write( "So we add -10 to both sides:\r\n" );
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document.write( "   42 - x² + x = 0\r\n" );
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document.write( "Secondly it is not in descending order,\r\n" );
document.write( "so we write the x² term first, then the\r\n" );
document.write( "x-term and finally the constant\r\n" );
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document.write( "  -x² + x + 42 = 0\r\n" );
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document.write( "Thirdly the leading coefficient (the coefficient of the\r\n" );
document.write( "x² term) should be positive, so we multiply it\r\n" );
document.write( "through by -1, changing all the signs\r\n" );
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document.write( "   x² - x - 42 = 0\r\n" );
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document.write( "Now it's easy to factor as\r\n" );
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document.write( "(x - 7)(x + 6) = 0\r\n" );
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document.write( "and solve with the zero-factor property:\r\n" );
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document.write( "x - 7 = 0;  x + 6 = 0\r\n" );
document.write( "    x = 7;      x = -6\r\n" );
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document.write( "Edwin
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