document.write( "Question 771334: A normal distribution has mean 63 and standard deviation 5. Find the data value if the z-score is .22 \n" ); document.write( "
Algebra.Com's Answer #470129 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! z = (x - mu)/sigma\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.22 = (x - 63)/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5*0.22 = x - 63\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.1 = x - 63\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1.1 + 63 = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "64.1 = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 64.1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The data value is 64.1 \n" ); document.write( " |