document.write( "Question 66248: I have a test coming up. I really need to know if I am on the right track.
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document.write( "1] list the first 4 terms of sequence given by the formula: s[n]=n!/n^2, n>=1.
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document.write( " I came up with 1, 1/2, 2/3, 3/2.\r
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document.write( "2} list the first 4 terms of sequence given by the recursion formula
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document.write( "a[n]=2a[n-1]+3, with a[1]=1. I came up with (1,3,7,15)\r
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document.write( "3] the sum of the first 500 terms of aritmetic series 1+4+7+...
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document.write( " I came up with 125,000 \n" );
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Algebra.Com's Answer #47010 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1] list the first 4 terms of sequence given by the formula: s[n]=n!/n^2, n>=1. \n" ); document.write( " I came up with 1, 1/2, 2/3, 3/2. \n" ); document.write( "Correct \n" ); document.write( "---------------------\r \n" ); document.write( "\n" ); document.write( "2} list the first 4 terms of sequence given by the recursion formula \n" ); document.write( "a[n]=2a[n-1]+3, with a[1]=1. I came up with (1,3,7,15) \n" ); document.write( "a(2)=2(1)+3=5 \n" ); document.write( "a(3)=2(5)+3=13 \n" ); document.write( "a(4)=2(13)+3=29 \n" ); document.write( "---------------------- \n" ); document.write( "3] the sum of the first 500 terms of aritmetic series 1+4+7+... \n" ); document.write( " I came up with 125,000 \n" ); document.write( "a(1)=1 \n" ); document.write( "d=3 \n" ); document.write( "a(500)=1+499*3=1498 \n" ); document.write( "S(500)=(500/2)(1+1498) \n" ); document.write( "S(500)=250(1499)=374,750 \n" ); document.write( "------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |