document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=771243>Question 771243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A compact disc (CD) is made such that the shortest distance between the edge of the centre hole and the edge of the disc is 53.0 mm. Find the radius of the centre-hole if 1.36% of the disc is removed in making the hole. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470061 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470061\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r = radius uf the center hole\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "r^2(pi) = 0.0136(r+53)^2 (pi)\r<BR>\n" );
document.write( "\n" );
document.write( "r^2 = 0.0136(r+53)^2\r<BR>\n" );
document.write( "\n" );
document.write( "(r/(r+53))^2 = 0.0136\r<BR>\n" );
document.write( "\n" );
document.write( "r/(r+53) = 0.116619\r<BR>\n" );
document.write( "\n" );
document.write( "r = (r+53)0.116619\r<BR>\n" );
document.write( "\n" );
document.write( "0.883381r =  6.180809\r<BR>\n" );
document.write( "\n" );
document.write( "r = 6.996765  \r<BR>\n" );
document.write( "\n" );
document.write( "(Rounding it r = 7)\r<BR>\n" );
document.write( "\n" );
document.write( "You can ask me more at: mthman@gmail.com\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );