document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=771131>Question 771131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The word problem: The height, h, in feet of an object above the ground is given by h(t)=-16t^2 + 64t + 190 where t is the time in seconds.  Find the time it takes the object to strike the ground and find the maximum height of the object.<BR>\n" );
document.write( "I have no idea what to do with this equation.  I have tried putting h in terms of t and solving from there, but it equals zero.  I do not know what else to do.  Thanks so much. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469995 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h, in feet of an object above the ground is given by h(t)=-16t^2 + 64t + 190 where t is the time in seconds.  Find the time it takes the object to strike the ground and find the maximum height of the object.<BR>\n" );
document.write( "I have no idea what to do with this equation.  I have tried putting h in terms of t and solving from there, but it equals zero.  I do not know what else to do.  Thanks so much.\r<BR>\n" );
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document.write( "h(t)=-16t^2 + 64t + 190 \r<BR>\n" );
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document.write( "at two times the height of the object = 0 when it starts and when it reaches the ground since this a parabola<BR>\n" );
document.write( "plug h=0<BR>\n" );
document.write( "-16t^2 + 64t + 190 =0\r<BR>\n" );
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document.write( "Find the roots of the equation by quadratic formula							<BR>\n" );
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document.write( "a=	-16	b=	64	c=	190		<BR>\n" );
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document.write( "b^2-4ac=	4096	-	-12160				<BR>\n" );
document.write( "b^2-4ac=	16256			<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%0916256%09%29 ALIGN=MIDDLE  ALT=\"sqrt%28%0916256%09%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >=	127.5<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29 ALIGN=MIDDLE  ALT=\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >							<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29 ALIGN=MIDDLE  ALT=\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >							<BR>\n" );
document.write( "x1=(	-64	+	127.5	)/	-32		<BR>\n" );
document.write( "x1=	-1.98						<BR>\n" );
document.write( "x2=(	-64	-127.5	) /	-32			<BR>\n" );
document.write( "x2=	5.98						<BR>\n" );
document.write( "Ignore negative value			mph				<BR>\n" );
document.write( "x	=	5.98 \r<BR>\n" );
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document.write( "time taken = 5.98 seconds\r<BR>\n" );
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document.write( "The maximum must occur at the vertex. So let’s find the vertex. We use the formula t =-b/2a (-64)/2*-16= 2 So we have t = 2 seconds.\r<BR>\n" );
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document.write( "So at 2 seconds the object reaches its maximum height.  we must find the value of the vertex, Find the value of h when t = 2. \r<BR>\n" );
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document.write( "We plug this in to the equation -16*(2)^2 + 64*2 + 190 = = 254 feet. <BR>\n" );
document.write( "So the maximum height is 254 feet.\r<BR>\n" );
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document.write( "					\r<BR>\n" );
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document.write( " </SPAN>\n" );
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