document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66270>Question 66270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide the fraction:\r<BR>\n" );
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document.write( "6p-18        3p-9<BR>\n" );
document.write( "-------   /  ------<BR>\n" );
document.write( "  9p          p^2+2p\r<BR>\n" );
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document.write( "The only step I understand of this is to flip the last equation making it look like this:<BR>\n" );
document.write( "6p - 18       p^2 + 2p<BR>\n" );
document.write( "-------   *  ---------<BR>\n" );
document.write( "  9p            3p-9\r<BR>\n" );
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document.write( "After this I am lost, can anyone help me figure out this problem please? Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46993 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6P-18)(P^2+2P)/9P(3P-9)<BR>\n" );
document.write( "2(3P-9)P(P+2)/9P(3P-9) FACTOR OUT THE Ps & THE (3P-9)<BR>\n" );
document.write( "2(P+2)/9 </SPAN>\n" );
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