document.write( "Question 771050: I have a 3000 gallon glycol heating system. I need to achieve a 50% mixture of glycol and water. Right now my 3000 gallons is around a 30% mixture, I want to buy 100% glycol and mix it to bring the 3000 gallons back up to a 50% mixture. Im trying to find out how many gallons i need to do this. I know it will raise the 3000 gallons as well which means I wont need the entire 3000 of the 30%. I couldnt begin to try and wrap my head around this. Anything you could do to help would be greatly appreciated. \n" ); document.write( "
Algebra.Com's Answer #469922 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! I have a 3000 gallon glycol heating system. I need to achieve a 50% mixture of glycol and water. Right now my 3000 gallons is around a 30% mixture, I want to buy 100% glycol and mix it to bring the 3000 gallons back up to a 50% mixture. Im trying to find out how many gallons i need to do this. I know it will raise the 3000 gallons as well which means I wont need the entire 3000 of the 30%. I couldnt begin to try and wrap my head around this. Anything you could do to help would be greatly appreciated. \n" ); document.write( "====================== \n" ); document.write( "Drain x gallons of the 30% to make space for the 100% to be added. \n" ); document.write( "---- \n" ); document.write( "(3000 - x)*30 + x*100 = 3000*50 \n" ); document.write( "x = 6000/7 gallons to drain \n" ); document.write( "x =~ 857 gallons to drain & replace. \n" ); document.write( " |