document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=770755>Question 770755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bill is 1 year less than twice as old as his brother John. If the sum of their ages is 20 years, how old are Bill and his brother John. How do I solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469738 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bill is 1 year less than twice his brother, John.<BR>\n" );
document.write( "B = (2J) - 1<BR>\n" );
document.write( "B + J = 20<BR>\n" );
document.write( "Replace B with (2J) - 1<BR>\n" );
document.write( "2J - 1 + J = 20<BR>\n" );
document.write( "3J = 20 + 1<BR>\n" );
document.write( "3J = 21<BR>\n" );
document.write( "J = 7<BR>\n" );
document.write( "John = 7 years old<BR>\n" );
document.write( "Bill = 13 years old<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );