document.write( "Question 770658: two years ago a father was five times as old as his son.two years later his age will be 8 more than 3 times the age of the son. find the present ages of father and son
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #469705 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Father = 5 * S \n" ); document.write( "F = 5S \n" ); document.write( "F = 5S \n" ); document.write( "Two years later \n" ); document.write( "F + 2 = 8 + 3(S + 2) \n" ); document.write( "Replace F with 5S \n" ); document.write( "5S + 2 = 8 + 3(S + 2) \n" ); document.write( "5S + 2 = 8 + 3S + 6 \n" ); document.write( "5S - 3S = 8 + 6 - 2 \n" ); document.write( "2S = 12 \n" ); document.write( "S = 6 \n" ); document.write( "Present ages: \n" ); document.write( "Son = 8 yrs old. \n" ); document.write( "Father = 32 years old. \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |