document.write( "Question 770658: two years ago a father was five times as old as his son.two years later his age will be 8 more than 3 times the age of the son. find the present ages of father and son
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Algebra.Com's Answer #469705 by Cromlix(4381)\"\" \"About 
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Father = 5 * S
\n" ); document.write( "F = 5S
\n" ); document.write( "F = 5S
\n" ); document.write( "Two years later
\n" ); document.write( "F + 2 = 8 + 3(S + 2)
\n" ); document.write( "Replace F with 5S
\n" ); document.write( "5S + 2 = 8 + 3(S + 2)
\n" ); document.write( "5S + 2 = 8 + 3S + 6
\n" ); document.write( "5S - 3S = 8 + 6 - 2
\n" ); document.write( "2S = 12
\n" ); document.write( "S = 6
\n" ); document.write( "Present ages:
\n" ); document.write( "Son = 8 yrs old.
\n" ); document.write( "Father = 32 years old.
\n" ); document.write( "Hope this helps.
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