document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=770457>Question 770457</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the following.\r<BR>\n" );
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document.write( "ln15+ln(2x-5)=7+ln3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469652 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469652\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the following. <BR>\n" );
document.write( "ln15+ln(2x-5)=7+ln3 <BR>\n" );
document.write( "ln15+ln(2x-5)-ln3=7<BR>\n" );
document.write( "ln(15*(2x-5)/3)=7<BR>\n" );
document.write( "convert to exponential form:base(e) raised to log of number(7)=number(15*(2x-5)/3)<BR>\n" );
document.write( "e^7=(15*(2x-5)/3)<BR>\n" );
document.write( "(30x-75)/3=e^7<BR>\n" );
document.write( "30x-75=3e^7<BR>\n" );
document.write( "30x=3e^7+75&#8776;3364.90<BR>\n" );
document.write( "x&#8776;112.16 </SPAN>\n" );
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