document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=770594>Question 770594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radioactive element americium-241 has a half-life of 432 years. Suppose we start with a 50-g mass of americium-241.<BR>\n" );
document.write( "How much will be left after 375 years? Compute the answer to three significant digits. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469615 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radioactive element americium-241 has a half-life of 432 years. Suppose we start with a 50-g mass of americium-241.<BR>\n" );
document.write( "How much will be left after 375 years? Compute the answer to three significant digits.<BR>\n" );
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document.write( "A(t) = Ao*(1/2)^(t/432)<BR>\n" );
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document.write( "A(375) = 50*(1/2)^(375/432) = 50*0.5479<BR>\n" );
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document.write( "A(375) = 27.4 grams<BR>\n" );
document.write( "=========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );