document.write( "Question 770449: Find the equation of the hyperbola whose centre is (1, 0), one focus is (6, 0) and transverse axis 6.
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Algebra.Com's Answer #469546 by KMST(5328)\"\" \"About 
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With the center at (1,0) and a focus 5 units to the right, at (6,0), you know that the focal distance is \"c=5\" anf that the transverse axis is along the x-axis.
\n" ); document.write( "(You also know that the other focus will be 5 units to the left of the center, at (4,0), and that is useful if you need to sketch the hyperbola).
\n" ); document.write( "The equation of a hyperbola with a transverse axis parallel to the x-axis and center at (h,k) is
\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"
\n" ); document.write( "In this case, since the center is (1,0), the equation is
\n" ); document.write( "\"%28x-1%29%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1\"
\n" ); document.write( "We need to find \"a\" and \"b\".
\n" ); document.write( "\"a\" is the distance from a vertex to the center, half of the length of the transverse axis.
\n" ); document.write( "If the transverse axis is 6, the vertices are 6 units apart,
\n" ); document.write( "and they are \"a=6%2F2=3\" units from the center.
\n" ); document.write( "(If you need to sketch the hyperbola, the vertices are 3 units to the right and 3 units to the left of the center, at (-2,0) and (4,0)).
\n" ); document.write( "The other number you need for the equation of the hyperbola is \"b\" such that
\n" ); document.write( "\"c%5E2=a%5E2%2Bb%5E2\".
\n" ); document.write( "So \"5%5E2=3%5E2%2Bb%5E2\"-->\"25=9%2Bb%5E2\"-->\"b%5E2=25-9\"-->\"b%5E2=16\"-->\"b=4\"
\n" ); document.write( "So the equation of the hyperbola in question is
\n" ); document.write( "\"highlight%28%28x-1%29%5E2%2F3%5E2-y%5E2%2F4%5E2=1%29\" or \"highlight%28%28x-1%29%5E2%2F9-y%5E2%2F16=1%29\"
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