document.write( "Question 770458: given log2=.3010, log7= .845, and log3=.4771 find the values of:\r
\n" ); document.write( "\n" ); document.write( "1)log28\r
\n" ); document.write( "\n" ); document.write( "2)log 144/49\r
\n" ); document.write( "\n" ); document.write( "please show me how to solve this. \n" ); document.write( "

Algebra.Com's Answer #469542 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+log%28+28+%29+=+log%28%28+3%2A7+%29%29+\"$
\n" ); document.write( " $\"+log%28%28+3%2A7+%29%29+=+log%28+3+%29+%2B+log%28+7+%29+\"$
\n" ); document.write( " $\"+log%28+3+%29+%2B+log%28+7+%29+=+.4771+%2B+.845+\"$
\n" ); document.write( "---------------------------------
\n" ); document.write( " $\"+log%28+144+%2F+49+%29+=+log%28+12%5E2+%2F+7%5E2+%29+\"$
\n" ); document.write( " $\"+log%28+12%5E2+%2F+7%5E2+%29+=+log%28+%28+12%2F7+%29%5E2+%29+\"$
\n" ); document.write( " $\"+log%28+%28+12%2F7+%29%5E2+%29+=+2%2Alog%28+12%2F7+%29+\"$
\n" ); document.write( " $\"+2%2Alog%28+12%2F7+%29+=+2%2A%28+log%28+12+%29+-+log%28+7+%29+%29+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+log%28%28+12+%29%29+=+log%28%28+3%2A2%2A2+%29%29+\"$
\n" ); document.write( " $\"+log%28%28+3%2A2%2A2+%29%29+=+log%283%29+%2B+2%2Alog%282%29+\"$
\n" ); document.write( " $\"+log%283%29+%2B+2%2Alog%282%29+=+.4771+%2B+2%2A.301+\"$
\n" ); document.write( "therefore:
\n" ); document.write( " $\"+log%28+144%2F49+%29+=+2%2A%28+log%28+12+%29+-+log%28+7+%29+%29+\"$
\n" ); document.write( " $\"+log%28+144%2F49+%29+=+2%2A%28+.4771+%2B+.602+-+.845+%29+\"$
\n" ); document.write( "( you can finish calculations )
\n" ); document.write( " \n" ); document.write( "

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