document.write( "Question 770305: solve for x in the equation: arc tan (x+1)+arc tan (x-1)=arc tan (12) \n" ); document.write( "
Algebra.Com's Answer #469531 by lwsshak3(11628)\"\" \"About 
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solve for x in the equation: arc tan (x+1)+arc tan (x-1)=arc tan (12)
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\n" ); document.write( "let angle A=arc tan (x+1)
\n" ); document.write( "let angle B=arc tan (x-1)
\n" ); document.write( "let angle C=arc tan (12)
\n" ); document.write( "A+B=C
\n" ); document.write( "tan(A+B)=tan(C)
\n" ); document.write( "..
\n" ); document.write( "Identity: tan(A+B)=(tanA+tanB)/(1-tanA*tanB)
\n" ); document.write( "(x+1+x-1)/(1-(x+1)(x-1))=2x/1-x^2+1=2x/(2-x^2)
\n" ); document.write( "tan(A+B)=tan(C)
\n" ); document.write( "2x/(2-x^2)=12
\n" ); document.write( "2x=24-12x^2
\n" ); document.write( "12x^2+2x-24=0
\n" ); document.write( "6x^2+x-12=0
\n" ); document.write( "(2x+3)(3x-4)=0
\n" ); document.write( "x=-3/2
\n" ); document.write( "or
\n" ); document.write( "x=4/3
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