document.write( "Question 66240This question is from textbook An Incremental Development
\n" ); document.write( ": please help to simplify\r
\n" ); document.write( "\n" ); document.write( "3i - 5\r
\n" ); document.write( "\n" ); document.write( "DIVIDED BY\r
\n" ); document.write( "\n" ); document.write( "-i^3 + 3i^2 \n" ); document.write( "
Algebra.Com's Answer #46950 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
please help to simplify
\n" ); document.write( "3i - 5
\n" ); document.write( "DIVIDED BY
\n" ); document.write( "-i^3 + 3i^2\r
\n" ); document.write( "\n" ); document.write( "i=sqrt(-1)
\n" ); document.write( "i^2=-1
\n" ); document.write( "i^3=(i^2)(i)=-sqrt(-1)
\n" ); document.write( "-i^3=sqrt(-1)=i
\n" ); document.write( "3i^2=3(-1)=-3\r
\n" ); document.write( "\n" ); document.write( "Now we have
\n" ); document.write( "(3i-5)/(i-3) Multiply numerator and denominator by (i+3) to get rid of the radical in the denominator and we have:\r
\n" ); document.write( "\n" ); document.write( "((3i-5)(i+3))/((i-3)(i+3)) Multiplying these out we get:\r
\n" ); document.write( "\n" ); document.write( "(3i^2-5i+9i-15)/(i^2-3i+3i-9)
\n" ); document.write( "(-3+4i-15)/-1-9
\n" ); document.write( "(4i-18)/-10 reduce by dividing both numerator and denominator by -2
\n" ); document.write( "(9-2i)/5\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor\r
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