document.write( "Question 770404: Monday Roger, goes to work, it takes him 35 minutes. Tuesday he goes to work and he goes 9 mph more than he did Monday and it took him 7 minutes less. how far did he go ? \n" ); document.write( "
Algebra.Com's Answer #469496 by josmiceli(19441) You can put this solution on YOUR website! Let \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "------------------------ \n" ); document.write( "Equation for Moday: \n" ); document.write( "(1) \n" ); document.write( "Equation for Tuesday: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "-------------------------- \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "------------------- \n" ); document.write( "Subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The distance to work and back is 42 mi \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |