document.write( "Question 66232This question is from textbook An Incremental Development
\n" ); document.write( ": Complete the square as an aid in graphing\r
\n" ); document.write( "\n" ); document.write( "y = -2x^2 + 8x - 6
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Algebra.Com's Answer #46949 by tutorcecilia(2152)\"\" \"About 
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y = -2x^2 + 8x - 6 [Eliminate the lead coefficient by dividing all terms by -2]\r
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\n" ); document.write( "\n" ); document.write( "-2x^2/-2 + 8x/-2 - 6/-2=0 [Set the equation equal to zero]
\n" ); document.write( "x^2 -4x +3-3=0=-3 [Subtract the \"C\" term from both sides of the eqaution]
\n" ); document.write( "x^2 -4x =-3 [Divide the \"B\" term by 2 and raise it to the 2nd power. Add the result to both sides of the equation]
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\n" ); document.write( "x^2 -4x +(4/2)^2=-3+(4/2)^2
\n" ); document.write( "x^2 -4x +2^2=-3+2^2 [Simplify]
\n" ); document.write( "x^2 -4x +2^2=-3+4
\n" ); document.write( "(x-2)(x-2)=1 [Factor the left side]
\n" ); document.write( "(x-2)^2=1
\n" ); document.write( "sqrt(x-2)^2=sqrt(1) [Take the square root of both sides]
\n" ); document.write( "x-2=+-1 [Solve for x]
\n" ); document.write( "So,
\n" ); document.write( "x=2+1=3
\n" ); document.write( "or
\n" ); document.write( "x=2-1=1
\n" ); document.write( "Check by plugging the values of x back into the original equation.
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