document.write( "Question 770321: Given 2^x=3^y=5^z=900^w
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Algebra.Com's Answer #469479 by AnlytcPhil(1806) $\"\"$ $\"About$

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Given 2^x=3^y=5^z=900^w
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document.write( "Suppose that\r\n" );
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document.write( "2^x = 3^y = 5^z = 900^w = A\r\n" );
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document.write( "Then (you can also use log instead of ln, as above):\r\n" );
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document.write( "log(2^x) = log(3^y) = log(5^z) = log(900^w) = log(A)\r\n" );
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document.write( "x·log(2) = y·log(3) = z·log(5) = w·log(900) = log(A)\r\n" );
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document.write( ", , , \r\n" );
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document.write( "*** xyz =  = ***\r\n" );
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document.write( "xy =  = \r\n" );
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document.write( "yz =  = \r\n" );
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document.write( "xz =  = \r\n" );
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document.write( "xy + yz + xz = \r\n" );
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document.write( "          \r\n" );
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document.write( "So 2w = \r\n" );
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document.write( "2w(xy+yz+xz)\r\n" );
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document.write( "          \r\n" );
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document.write( "And that's what xyz was shown equal to above, marked ***\r\n" );
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document.write( "Edwin

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