document.write( "Question 770321: Given 2^x=3^y=5^z=900^w
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Algebra.Com's Answer #469478 by Edwin McCravy(20060) $\"\"$ $\"About$

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Given 2^x=3^y=5^z=900^w
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document.write( "Suppose that \r\n" );
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document.write( "2^x = 3^y = 5^z = 900^w = A\r\n" );
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document.write( "Then,\r\n" );
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document.write( "ln(2^x) = ln(3^y) = ln(5^z) = ln(900^w) = ln(A)\r\n" );
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document.write( "x·ln(2) = y·ln(3) = z·ln(5) = w·ln(900) = ln(A)\r\n" );
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document.write( ", , , \r\n" );
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document.write( "*** xyz =  = ***       \r\n" );
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document.write( "xy =  = \r\n" );
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document.write( "yz =  = \r\n" );
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document.write( "xz =  =   \r\n" );
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document.write( "xy + yz + xz = \r\n" );
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document.write( "          \r\n" );
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document.write( "So 2w =    \r\n" );
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document.write( "2w(xy+yz+xz)\r\n" );
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document.write( "          \r\n" );
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document.write( "And that's what xyz was shown equal to above, marked ***      \r\n" );
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document.write( "Edwin

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