document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=770359>Question 770359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Investigators at a traffic accident use the equation: D = 0.04v2 + 0.8v where v is the velocity (speed in mph) of the car before starting to stop and D is the   stopping distance (length of the skid marks). If the skid marks are 192 feet long, how fast was the car traveling prior to the accident?   <BR>\n" );
document.write( "Please provide the steps. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469474 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Investigators at a traffic accident use the equation: D = 0.04v2 + 0.8v where v is the velocity (speed in mph) of the car before starting to stop and D is the stopping distance (length of the skid marks). If the skid marks are 192 feet long, how fast was the car traveling prior to the accident?<BR>\n" );
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document.write( "Solve:<BR>\n" );
document.write( "0.04v^2+0.8v-192 = 0<BR>\n" );
document.write( "4v^2 + 80v - 19200 = 0<BR>\n" );
document.write( "v^2  +20v - 4800 = 0<BR>\n" );
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document.write( "(v-60)(V+80) = o<BR>\n" );
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document.write( "v = 60 mph<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= <BR>\n" );
document.write( " </SPAN>\n" );
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