document.write( "Question 770277: A group of fishermen rented a boat for $2400. Two of the men withdrew from the party and as result, the share of each of those remaining was increased by 100. How many were in the original group? \n" ); document.write( "
Algebra.Com's Answer #469412 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A group of fishermen rented a boat for $2400. Two of the men withdrew from the party and as result, the share of each of those remaining was increased by 100. How many were in the original group? \n" ); document.write( ". \n" ); document.write( "Let x = original number in group \n" ); document.write( "and y = original share \n" ); document.write( ". \n" ); document.write( "xy = 2400 (equation 1) \n" ); document.write( "(x-2)(y+100) = 2400 (equation 2) \n" ); document.write( ". \n" ); document.write( "solve equation 1 for y: \n" ); document.write( "xy = 2400 \n" ); document.write( "y = 2400/x \n" ); document.write( "substitute above into equation 2 and solve for x: \n" ); document.write( "(x-2)(y+100) = 2400 \n" ); document.write( "(x-2)(2400/x+100) = 2400 \n" ); document.write( "multiplying both sides by x: \n" ); document.write( "(x-2)(2400+100x) = 2400x \n" ); document.write( "dividing both sides by 100: \n" ); document.write( "(x-2)(24+x) = 24x \n" ); document.write( "24x+x^2-48-2x = 24x \n" ); document.write( "x^2+22x-48 = 24x \n" ); document.write( "x^2-2x-48 = 0 \n" ); document.write( "(x+6)(x-8) = 0 \n" ); document.write( "x = {-6, 8} \n" ); document.write( "throw out the negative solution (extraneous) leaving \n" ); document.write( "x = 8 (answer) \n" ); document.write( " \n" ); document.write( " |