document.write( "Question 770142: an airplane made a trip of 350 miles against the wind in an hour and 10minutes.returning w/the wind it took only an hour.find the speed of the plane? in still air and in the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #469383 by ramkikk66(644)\"\" \"About 
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document.write( "Let x be the speed of the plane and y be the speed of wind in mph.\r\n" );
document.write( "While travelling against wind, effective speed is (x-y) mph\r\n" );
document.write( "Time taken to travel 350 miles is 1 hour 10 min = 7/6 hours\r\n" );
document.write( "So \"350%2F%28x-y%29=7%2F6\"\r\n" );
document.write( "\"x+-+y+=+350%2A6%2F7+=+300\" ----> eqn 1\r\n" );
document.write( "While travelling with the wind, effective speed is (x+y) mph\r\n" );
document.write( "Time taken to travel 350 miles is 1 hour\r\n" );
document.write( "So \"350%2F%28x%2By%29=1\"\r\n" );
document.write( "\"x+%2B+y+=+350\"   -----> eqn 2\r\n" );
document.write( "Adding (1) and (2)\r\n" );
document.write( "\"2%2Ax+=+650\"\r\n" );
document.write( "\"x+=+325\"\r\n" );
document.write( "since x + y = 350, y = 350 - 325 = 25\r\n" );
document.write( "So speed of plane = \"red%28350%29\" mph\r\n" );
document.write( "Wind speed = \"red%2825%29\" mph\r\n" );
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