document.write( "Question 770143: Solution for cos4x=cos2x
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Algebra.Com's Answer #469322 by Alan3354(69443)\"\" \"About 
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Solution for cos4x=cos2x
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\n" ); document.write( "cos(2A) = 2cos^2(A) - 1 double angle formula
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\n" ); document.write( "cos4x=cos2x
\n" ); document.write( "2cos^2(2x) - 1 = cos(2x)
\n" ); document.write( "2cos^2(2x) - cos(2x) - 1 = 0
\n" ); document.write( "(2cos + 1)*(cos - 1) = 0
\n" ); document.write( "cos(2x) = 1
\n" ); document.write( "2x = 0 + 2n*pi, n = 0,1,2,3...
\n" ); document.write( "x = 0 + n*pi, n = 0,1,2,3...
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\n" ); document.write( "cos(2x) = -1/2
\n" ); document.write( "2x = 2pi/3, 4pi/3 + 2n*pi, n = 0,1,2,3...
\n" ); document.write( "x = pi/3, 2pi/3 + n*pi, n = 0,1,2,3...
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