document.write( "Question 66211This question is from textbook College Algebra
\n" ); document.write( ": A ballet performance brought in $61,800 o the sale of 3000 tickets. If the tickets sold for $14 and $25, how many of each were sold? \n" ); document.write( "
Algebra.Com's Answer #46930 by ptaylor(2198)\"\" \"About 
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Let x=number sold for $25
\n" ); document.write( "Then 3000-x=number sold for $14\r
\n" ); document.write( "\n" ); document.write( "Now we are told that the amount brought in by the sale of the $25 tickets (25x) plus the amount brought in by the sale of the $14 tickets (14(3000-x)) was $61,800. So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "25x+14(3000-x)=61,800 simplifying we have
\n" ); document.write( "25x+42,000-14x=61,800 collecting x's and subtracting 42,000 from each side:\r
\n" ); document.write( "\n" ); document.write( "11x=61,800-42,000 and
\n" ); document.write( "11x=19,800
\n" ); document.write( "x=1800 number of $25 tickets sold\r
\n" ); document.write( "\n" ); document.write( "3000-x=3000-1800=1200 number of $14 tickets sold\r
\n" ); document.write( "\n" ); document.write( "ck\r
\n" ); document.write( "\n" ); document.write( "1800(25)+1200(14)=61,800
\n" ); document.write( "45,000+16,800=61,800
\n" ); document.write( "61,800=61,800\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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