document.write( "Question 770135: You went trout fishing. You caught trout with lengths (in inches) of 8 8/5, 10 1/2, 9 1/2, 8 3/4, 10 2/3, and 9 5/6. What is the average length of trout you caught? \n" ); document.write( "
Algebra.Com's Answer #469296 by Cromlix(4381)\"\" \"About 
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8 8/5, 10 1/2, 9 1/2, 8 3/4, 10 2/3, and 9 5/6.
\n" ); document.write( "Convert to fractions:
\n" ); document.write( "48/5 + 21/2 + 19/2 + 35/4 + 32/3 + 59/6
\n" ); document.write( "Add 21/2 + 19/2 = 41/2
\n" ); document.write( "48/5 + 41/2 + 35/4 + 32/3 + 59/6
\n" ); document.write( "Common denominator = 60
\n" ); document.write( "= (576 + 1230 + 525 + 640 + 590)/60
\n" ); document.write( "= 3561/60
\n" ); document.write( "= 59.35 inches
\n" ); document.write( "Divide 59.35 by 6
\n" ); document.write( "= 9 9/10 inches (average).
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "
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