document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=770134>Question 770134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You need a piece of trim 6 5/8 yards long to complete craft project. You have 6 3/4 yards long left over from another project. Is the trim long enough? What is the difference between the trim you have and the needed trim? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469293 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6 3/4 - 6 5/8<BR>\n" );
document.write( "Convert to fraction<BR>\n" );
document.write( "27/4 - 53/8<BR>\n" );
document.write( "Common denominator = 8<BR>\n" );
document.write( "54 - 53/8<BR>\n" );
document.write( "= 1/8 of a yard left over.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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