document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66208>Question 66208</A>: <I><SPAN STYLE=\"word-break: break-all;\"> evaluate \r<BR>\n" );
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document.write( "e^2ln3<BR>\n" );
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document.write( "(2^3*2^-5)/2^-7<BR>\n" );
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document.write( "log4 64<BR>\n" );
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document.write( "log4 32<BR>\n" );
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document.write( "log2 4th root(1/8)<BR>\n" );
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document.write( "log 25 +log 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46924 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> evaluate \r<BR>\n" );
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document.write( "e^2ln3 = [e^(ln3)]^2 =[3]^2 = 9<BR>\n" );
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document.write( "(2^3*2^-5)/2^-7 = 2^-2 / 2^-7 = 2^5 = 32<BR>\n" );
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document.write( "log4 64 = log4 (4^3) = 3<BR>\n" );
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document.write( "log4 32 = log2 32 / log2 4 = 5/2<BR>\n" );
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document.write( "log2 4th root(1/8) = (1/4)log2 [2^-3] = (1/4)(-3) = -3/4<BR>\n" );
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document.write( "log 25 +log 4 = log (25*4)= log 100 = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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