document.write( "Question 769984: solve 1+cosx=sinx, for [0,2pi)
\n" ); document.write( "I was told to square both sides, but got stuck at ,
\n" ); document.write( "1+2cosx+cosx^2=sinx^2
\n" ); document.write( "

Algebra.Com's Answer #469183 by reviewermath(1029)\"\" \"About 
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Q:
\n" ); document.write( "solve 1+cosx=sinx, for [0,2pi)
\n" ); document.write( "I was told to square both sides, but got stuck at ,
\n" ); document.write( "1+2cosx+cosx^2=sinx^2
\n" ); document.write( "------------------------------------------------------
\n" ); document.write( "A:
\n" ); document.write( "Use the identity \"cos%5E2%28x%29+%2B+sin%5E2%28x%29+=+1\" OR \"sin%5E2%28x%29+=+1+-+cos%5E2%28x%29\"
\n" ); document.write( "Substitute the identity on the right side of the equation \"1%2B2%2Acos%28x%29%2Bcos%5E2%28x%29=sin%5E2%28x%29\".
\n" ); document.write( "\"1%2B2%2Acos%28x%29%2Bcos%5E2%28x%29=1+-+cos%5E2%28x%29\"
\n" ); document.write( "\"2%2Acos%5E2%28x%29+%2B+2%2Acos%28x%29=+0\"
\n" ); document.write( "\"%28cos%28x%29%29%2A%282%2Acos%28x%29+%2B+2%29=+0\"
\n" ); document.write( "\"cos%28x%29\" = 0 OR \"2%2Acos%28x%29+%2B+2\" = 0
\n" ); document.write( "\"cos%28x%29\" = 0 OR \"cos%28x%29\" = -1
\n" ); document.write( "x = \"highlight%28pi%2F2%29\" OR \"highlight%28pi%29\"
\n" ); document.write( "
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