document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=769984>Question 769984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve 1+cosx=sinx, for [0,2pi)<BR>\n" );
document.write( "I was told to square both sides, but got stuck at ,<BR>\n" );
document.write( "1+2cosx+cosx^2=sinx^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469182 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
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document.write( "You did the first step is 100% correct by squaring both sides. You will have:\r<BR>\n" );
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document.write( "1 + 2Cos(x) + cos^2(x) = Sin^2(x)\r<BR>\n" );
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document.write( "Then you will use the formula: sin^2 (x) + cos^2 (x) = 1\r<BR>\n" );
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document.write( "Then sin^2 (x) = 1 - cos^2(x)\r<BR>\n" );
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document.write( "1 + 2cos(x) + cos^2(x) = 1 - cos^2(x)\r<BR>\n" );
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document.write( "2cos^2(x) + 2cos(x) = 0\r<BR>\n" );
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document.write( "2cos(x) (cos(x) + 1) = 0\r<BR>\n" );
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document.write( "cos(x) =0  OR cos(x) + 1 = 0\r<BR>\n" );
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document.write( "You can solve from here :)\r<BR>\n" );
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document.write( "John(john100185@yahoo.com) </SPAN>\n" );
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