document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=732188>Question 732188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The value  of 4y^(-2/3) + 3y^(2/3) + 2y^(-1/3) + 5y^(1/3) when y = 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469177 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4y^(-2/3) + 3y^(2/3) + 2y^(-1/3) + 5y^(1/3)=\r<BR>\n" );
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document.write( "4*8^(-2/3) + 3*8^(2/3) + 2*8^(-1/3) + 5*8^(1/3)=\r<BR>\n" );
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document.write( "4/4 + 3*4 + 2/2 + 5*2=\r<BR>\n" );
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document.write( "1 +12 + 1 + 10=\r<BR>\n" );
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document.write( "24 </SPAN>\n" );
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