document.write( "Question 769962: 1) Find the smallest positive value of t for which f(t) = 2 sin (2t − π/6) is the following.\r
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document.write( " f(t) attains a maximum value.
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document.write( "2) Find all values of t in the interval [0, 2π] satisfying the given equation. (Enter your answers as a comma-separated list.)\r
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document.write( "sqrt(6) sin 2t + 3 tan 2t = 0\r
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document.write( "t = \n" );
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Algebra.Com's Answer #469172 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 1) Find the smallest positive value of t for which f(t) = 2 sin (2t − π/6) is the following. \n" ); document.write( "f(t) attains a maximum value. \n" ); document.write( "sin is maximum at π/2 \n" ); document.write( "sin(2t-π/6)=sin(π/2) \n" ); document.write( "2t-π/6=π/2 \n" ); document.write( "2t=π/2+π/6=4π/6=2π/3 \n" ); document.write( "t = π/3 \n" ); document.write( "f(t) attains a maximum value when t=π/3 \n" ); document.write( ".. \n" ); document.write( "2) Find all values of t in the interval [0, 2π] satisfying the given equation. (Enter your answers as a comma-separated list.) \n" ); document.write( "sqrt(6) sin 2t + 3 tan 2t = 0 \n" ); document.write( "√6sin(2t)+(3sin(2t)/cos(2t))=0 \n" ); document.write( "LCD:cos(2t) \n" ); document.write( "√6sin(2t)cos(2t)+3sin(2t)=0 \n" ); document.write( "sin(2t)(√6cos(2t)+3)=0 \n" ); document.write( ".. \n" ); document.write( "sin(2t)=0 \n" ); document.write( "2t=0, π,2π \n" ); document.write( "t=0, π/2,π \n" ); document.write( ".. \n" ); document.write( "√6cos(2t)+3)=0 \n" ); document.write( "√6cos(2t)=-3 \n" ); document.write( "cos(2t)=-3/√6≈-1.22... (reject, -1 ≤ cos(2t) ≤ 1) \n" ); document.write( ".. \n" ); document.write( "values of t in the interval [0, 2π]=0, π, 2π \n" ); document.write( " \n" ); document.write( " |