document.write( "Question 769979: A store mixes Kentucky bluegrass worth $11 per pound and rye grass worth $15 per pound. The mixture is to sell for $14 per pound. Find how much of e should be to make a 552 pound mixture?\r
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document.write( "How many pounds of rye grass should be in the mixture? \n" );
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Algebra.Com's Answer #469170 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A store mixes Kentucky bluegrass worth $11 per pound and rye grass worth $15 per pound. The mixture is to sell for $14 per pound. Find how much of e should be to make a 552 pound mixture? \n" ); document.write( "How many pounds of rye grass should be in the mixture? \n" ); document.write( "-------- \n" ); document.write( "Quantity:: k + r = 552 lbs \n" ); document.write( "Value::::11k+15r = 14*552 dollars \n" ); document.write( "----------------------------------- \n" ); document.write( "Modify to eliminate:: \n" ); document.write( "11k + 11r = 11*552 \n" ); document.write( "11k + 15r = 14*552 \n" ); document.write( "--------------------- \n" ); document.write( "4r = 3*552 \n" ); document.write( "r = 3*138 \n" ); document.write( "r = 414 lbs (amt. of rye needed) \n" ); document.write( "----- \n" ); document.write( "k = 552-414 = 138 lbs (amt. of blue grass needed) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |