document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=769942>Question 769942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two years ago, Dilip age was three times as old as his son and two years hence, twice his age will be equal to five times that of his son. Find their present age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469129 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dilip age was three times as old as his son<BR>\n" );
document.write( "D = 3S<BR>\n" );
document.write( "two years hence, twice his age will be equal to five times that of his son.<BR>\n" );
document.write( "2(D + 2) = 5(S + 2)<BR>\n" );
document.write( "Replace D on left hand side with 3S<BR>\n" );
document.write( "2(3S + 2) = 5(S + 2)<BR>\n" );
document.write( "6S + 4 = 5S + 10<BR>\n" );
document.write( "6S - 5S = 10 - 4<BR>\n" );
document.write( "S = 6.<BR>\n" );
document.write( "Dilip is aged 20 years old<BR>\n" );
document.write( "Son is 8 years old<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );