document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=769865>Question 769865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'll seriously love you forever if you help me. :'(\r<BR>\n" );
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document.write( " SQRT(4a + 1) = 1<BR>\n" );
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document.write( "CUBERT(3x - 8) = 1<BR>\n" );
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document.write( " SQRT(x + 4) = SQRT(x) - 2<BR>\n" );
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document.write( " Assume that a surveyor stands at the top of a mountain that is \"h\" feet tall. If the distance (in feet) that he can see is defined by d = 3200.2 SQRT(h), then answer the following. (a) How far can the surveyor see from the top of a 2000-foot mountain? (b) How tall is the mountain, if the surveyor can see 15 miles? (Note: 1 mile equals 5280 feet.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #469118 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=469118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SQRT(4a + 1) = 1\r<BR>\n" );
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document.write( "square both sides of equation4a+1=1<BR>\n" );
document.write( "4x=1-1<BR>\n" );
document.write( "4a=0<BR>\n" );
document.write( "a=0<BR>\n" );
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document.write( "CUBERT(3x - 8) = 1<BR>\n" );
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document.write( "square both sides<BR>\n" );
document.write( "3x-8 =1<BR>\n" );
document.write( "3x=8<BR>\n" );
document.write( "x=8/3<BR>\n" );
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document.write( " SQRT(x + 4) = SQRT(x) - 2\r<BR>\n" );
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document.write( "square both sides\r<BR>\n" );
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document.write( "x+4 = x-4sqrt(x)+4\r<BR>\n" );
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document.write( "x=0\r<BR>\n" );
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document.write( " Assume that a surveyor stands at the top of a mountain that is \"h\" feet tall. If the distance (in feet) that he can see is defined by d = 3200.2 SQRT(h), then answer the following. (a) How far can the surveyor see from the top of a 2000-foot mountain? (b) How tall is the mountain, if the surveyor can see 15 miles? (Note: 1 mile equals 5280 feet.)\r<BR>\n" );
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document.write( "its is substitution problem </SPAN>\n" );
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