document.write( "Question 769871: Establish the Identity:\r
\n" ); document.write( "\n" ); document.write( "(secθ-tanθ)^2+1 / secθcscθ-tanθcscθ =2tanθ \n" ); document.write( "
Algebra.Com's Answer #469094 by lwsshak3(11628)\"\" \"About 
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Establish the Identity:
\n" ); document.write( "(secθ-tanθ)^2+1 / secθcscθ-tanθcscθ =2tanθ
\n" ); document.write( "start with left-hand side
\n" ); document.write( "(sec^2-2sectan+tan^2+1)/(seccsc-tancsc)
\n" ); document.write( "tan^2+1=sec^2
\n" ); document.write( "(sec^2-2sectan+sec^2)/(csc(sec-tan))
\n" ); document.write( "(2sec^2-2sectan)/(csc(sec-tan))
\n" ); document.write( "2sec(sec-tan)/(csc(sec-tan))
\n" ); document.write( "2sec/csc=2(1/cos)/(1/sin)=2sin/cos=2tan
\n" ); document.write( "verified:
\n" ); document.write( "left-hand side =right-hand side\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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