document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66165>Question 66165</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Samuel has a 10% solution of hydrochloric acid and a 50% solution of hydrochloric acid. How much of each type must be mixed to obtain 60 liters of a 25% solution of hydrochloric acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46909 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .5x+.1(60-x)=60*.25<BR>\n" );
document.write( ".5x+6-.1x=15<BR>\n" );
document.write( ".4x=15-6<BR>\n" );
document.write( ".4x=9<BR>\n" );
document.write( "x=9/.4<BR>\n" );
document.write( "x=22.5 liters of 50% & (60-22.5)=37.5 liters of 10% are needed <BR>\n" );
document.write( "proof<BR>\n" );
document.write( ".5*22.5+.1(60-22.5)=60*.25<BR>\n" );
document.write( "11.25+.1(37.5)=15<BR>\n" );
document.write( "11.25+3.75=15<BR>\n" );
document.write( "15=15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );