document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66177>Question 66177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46902 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+4(x+1)=46<BR>\n" );
document.write( "2x+4x+4=46<BR>\n" );
document.write( "6x=46-4<BR>\n" );
document.write( "6x=42<BR>\n" );
document.write( "x=7 solution then <BR>\n" );
document.write( "7+1=8 solution<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "2*7+4*8=14+32=46<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );