document.write( "Question 66170: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #46901 by algebrapro18(249) $\"\"$ $\"About$

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if the width is equal to x then the length is equal to 2x+2 which gives us the following equation:
\n" ); document.write( "2(2x+2) + 2x = 52
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\n" ); document.write( "\n" ); document.write( "now solving the equation we get:
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\n" ); document.write( "\n" ); document.write( "2(2x + 2) + 2x = 52
\n" ); document.write( "4x + 4 + 2x = 52
\n" ); document.write( "6x + 4 = 52
\n" ); document.write( "6x = 48
\n" ); document.write( "x = 8
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\n" ); document.write( "\n" ); document.write( "so we know that the width is 8 and now we solve for the length
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\n" ); document.write( "\n" ); document.write( "length = 2x+2
\n" ); document.write( "length = 2(8)+2
\n" ); document.write( "length = 18 \n" ); document.write( "

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