document.write( "Question 769697: I am unsure of how to answer this question.
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\n" ); document.write( "PQRS is a rhombus. the diagonals PR and QS intersect at T\r
\n" ); document.write( "\n" ); document.write( "Prove that:\r
\n" ); document.write( "\n" ); document.write( "a. diagonals PR and SQ bisect the angles for the rhombus.\r
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\n" ); document.write( "\n" ); document.write( "thank you. hope to hear from you soon.
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Algebra.Com's Answer #469004 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Take diagonal PR. It divides the rhombus into 2 triangles\r\n" );
document.write( "PQR and PTR.\r\n" );
document.write( "These 2 triangles are congruent - why? Because 2 sides PQ and TR are equal, so are\r\n" );
document.write( "PT and QR (sides of a rhombus are equal) and the side PR is common.\r\n" );
document.write( "So the corresponding angles of the 2 triangles are equal.\r\n" );
document.write( "i.e. Angle PRT = angle PRQ\r\n" );
document.write( "So PR bisects the angle R and also angle P.\r\n" );
document.write( "You can similarly prove for the other diagonal QT also.\r\n" );
document.write( "Hope you got it :)\r\n" );
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